Question

*4 A sandbag is released from a balloon which is ascend-
ing with a steady vertical velocity of 8 ms. If the
sandbag hits the ground 15 s later, what was the
height of the balloon above the ground when it was
released?​

Answer 1

Answer:

Given :-

Force applied = 20000 N

Area = 0.1 m²

To Find :-

The pressure exerted on the ground.

Analysis :-

Here we are given with the force and the area.

In order to find the pressure exerted substitute the values given in the question such that pressure is equal to force divided by area and find the pressure exerted on the ground accordingly.

Solution :-

We know that,

f = Force

p = Pressure

a = Area

Using the formula,

Pressure=ForceArea‾\underline{\boxed{\sf Pressure=\dfrac{Force}{Area} }}

Pressure=

Area

Force

Given that,

Force (f) = 20000 N

Area (a) = 0.1 m²

Substituting their values,

⇒ p = f/a

⇒ p = 20000/0.1

⇒ p = 200000 N/m²

Therefore, the pressure exerted on the ground is 200000 N/m².