Question

4. A set of 25 tuning forks is arranged in order of
decreasing frequency. Each fork gives 3 beats with
succeeding one. The first fork is octave of the last
Calculate the frequency of the first and 16th fork.
​

Answer 1

Answer:

Solution

Let frequency of last fork be n.

∴ Freq. of 1st fork =2n,

freq. of 2nd fork =[2n−3],

freq. of 3rd fork (2n−6)

=2n−3(3−1) and so on

∴ freq. of 25th fork =2n−3(25−1)=n

∴ n=72

Hence, freq. of 1st fork =2n=144Hz

and freq. of 16th fork =144−3(16−1)

= 99Hz