Question

4. A shell of mass 10kg is fired with a velocity of 80ms' making an angle 30° with the vertical. Find its momentum when the shell reaches the highest position a) 0 kg.m/sec b) 400/3 kg.m/sec c) 400 kg.m/sec d) 80073 kg.m/sec Answer the question with properly explaination​

Answer 1

Given : mass = 10kg

velocity = 80m/s

angle made horizontally = 30°

Now solutions:

Here angle made = 30°

BUT with respect to its height

it's angle will be 60°

( because it is right angle triangle

total angle = 90°

90°-30° = cos60°

so momentum of the body is

p = mass × velocity × cos 60°

p = 10×80×1/2(because cos 60° = 1/2)

p = 400kgm/s

Answer

: 400kgm/s