Question

4. A small block of wood of mass 9 kg is floating on water. Find the force of buoyancy acting on the block. (g = 10 ms2​

Answer 1

Answer:

1225 N

Explanation:

Density of water, ρ=1000 kg m

−3

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the liquid displaced.

Volume of water displaced = 50×50×50×10

−6

m

3

=0.125 m

3

Weight of water displaced = 0.125×1000×9.8=1225 N

X=1225

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