Question

4) A solid of mass 80g and at 75oC is dropped into 150g of water at 15oC which is contained in a copper calorimeter of mass 50g. The final temperature attained by the mixture is 25oC. If the specific heat capacity of copper and water are 400 J kg-1K-1 and 4200 J kg-1K-1 respectively. Calculate the specific heat capacity of the solid in SI unit.

Answer 1

Answer:

Heat energy given by metal piece =m⋅c⋅ΔT

1

=20×0.3×(100−22)

=468J

Heat energy gained by water =m

w

×c

w

×ΔT

2

=m

w

×4.2×(22−20)

=m

w

×8.4J

Heat energy gained by calorimeter =m

c

×c

c

×ΔT

2

=50×0.42×(22−20)

=42J

By principle of calorimeter:

Heat lost = Heat gained

Heat energy given by metal = Heat energy gained by water + Heat energy gained by calorimeter

468=m

w

×8.4+42

m

w

=

8.4

468−42

=50.7g

Therefore, the mass f water used in the calorimeter is 50.7g.

Answer 2

Explanation:

hope it helps .

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