Question

4. (a) Solve (2D²D' - 3DD'2 +D'3)= 0​

Answer 1

$\bf \: what \: you \: get \: when \: you \: remove \: a \: cup \: of \: water \: from \: sea . \\ \\ \bf</p><p>yhea you get sea.</p><p> \\ \\ \bf</p><p>sea=cup of water + sea</p><p> \\ \\ \bf</p><p>sea=root(cup root(sea))</p><p> \\ \\ \bf</p><p>square both sides</p><p> \\ \\ \bf</p><p>sea^2=cup+sea</p><p> \\ \\ \bf</p><p>sea^2-sea-cup=0</p><p> \\ \\ \bf</p><p>[sea -1/2]^2 -cup -1/4=0 \\ \\ \bf</p><p>sea=1/2+(or -) root(cup+1/4 \\ \\ \bf</p><p>sea = 1/2+(or -)root(3+1/4) = 1/2+(or-)root(7/4)</p><p></p><p></p><p></p><p></p><p></p><p>$