Question

4 a square minus 12 a b + 9 b square - 16 C square​

Answer 1

Answer:

$(4a^{2} -12ab+9b^{2}) -16c^{2}$

The identity $(a-b)^2= a^2- 2ab + b^2$ has been used in the first part of the equation.

Step-by-step explanation:

Using the identity, we have

[$(2a)^2$ - 2(2a)(3b) +$(3b)^2$] - $(4c)^2$

$(2a-3b)^{2}$ -  $(4c)^2$

Using $a^2 - b^2 = (a+b) (a-b)$

=(2a-3b-4c)(2a-3b+4c)