Question

4 a square minus- 4 b square + 4a + 1

Answer 1

$4 {a}^{2} - 4 {b}^{2} + 4a + 1$
$= {(2a + 1)}^{2} - {(2b)}^{2}$
$= (2a + 1 + 2b)(2a + 1 - 2b)$

Answer 2

Hey there! ☺☻☺

$4a^2 - 4b^2 + 4a + 1\\=4a^2 + 4a + 1 - 4b^2\\= (2a)^2 + 2\times2a + 1^2 - (2b)^2\\=(2a + 1)^2 - (2b)^2\\=\boxed{\boxed{\bold{(2a+1+2b)(2a+1-2b)}}}$

Hope It Helps You! ☺☻☺