Question

4. A steady current of 2.5 A exist in a wire for 4 min
a) How much total charge passed through a given section in the circuit
during those 4 min.
b) How many
electrons would this be ?

​answer me faast...

Answer 1

1.

current = (charge passed)/time

charge passed = 2.5 × 4 × 60 = 600 coulombs

2.

$1coulomb = 6.24 \times {10}^{24} electrons$

so, this makes

$3.744 \times {10}^{27} electrons$

Answer 2

Concept introduction:

Electrical charge carriers, often electrons or atoms lacking in electrons, travel as current. The capital letter I is a typical way to represent current. The ampere, denoted by the letter A, is the common unit.

Explanation:

Given that, a steady current of $2.5$ A exist in a wire for $4$ min.

We have to find, amount of charge passed and number of electrons passed in the given time.

According to the question,

We know I = Q/t

⇒Q = I*t = $2.5*4*60 = 600$ coulomb

Now,

$1$C = $6.24*10^{18}$ electrons

∴ Number electrons =  $6.24*10^{18}$ $*600$ = $37.44*10^{20}$

Final Answer:

Total charge = $600$C

Number of electrons =  $37.44*10^{20}$

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