Question

4. A stone is thrown in a vertically upward direction with a velocity of 5 m s. If the
acceleration of the stone during its motion is 10 m s2 in the downward direction, what will
be the height attained by the stone and how much time will it take to reach there?​

Answer 1

Answer:

5 points = 5 thanks

have a great day ahead

Answer 2

Explanation:

Here given

u= 5m/s

a = -10m/s²

v = 0(since the stone will come to rest at some point)

to find, s =

using 3rd eq of motion

2as = v²-u²

s = 0²-5²/2(-10)

s = 0-25/-20

s = -25/-20

s = 5/4

s = 1.25m

using 1st eq of motion

v = u + at

t = v-u/a

t = 0-5/-10

t = -5/-10

t = 1/2

t = 0.5s