Question

4. A stone is thrown vertically up from a bridge
with velocity 3 ms. If it strikes the water
under the bridge after 2 s, the bridge is at a
height of
(g-10 ms)​

Answer 1

Answer:

Let the stone is thrown from a building of height 'H'

u = +3m/s g = -10m/s² t = 2s

-H = ut + gt²/2

-H = 6 + (-10 x 4)/2

-H = 6 - 20 = -12

H = 12m

note: -H because the displacement is downwards and downwards is assumed negative direction