Question

4. A stone thrown vertically upwards reaches the maximum height in 3 m, if theacceleration of the stone be 10 m/s2, calculate its initial velocity.

Answer 1

Answer:

Explanation:

Given

h= 3m

g = -10m/s^2

v = 0m/s

now

v^2 = u^2+2gh

0 = u^2 +2(-10)(3)

u^2 = 60

u = 4√15m/s

Answer 2

Initial velocity of the stone, u = ?

Final velocity of stone, v = 0

Acceleration due to gravity, g=−9.8m/s²

Time, t = 3 sec

Using relation, v = u + gt

0=u−9.8×3

u = 29.4 m/s

hope it helps you