Question

4
A student goes from his house to his friend's house with speed v. Finding the door of his friends's closed,
return back to his own house with the speed vz. Then the average speed of the student is​

Answer 1

Answer:

verage speed = (v1+v2)/2 Net displacement is 0

Explanation:

average speed formula is (speed1+speed2)/2 so average speed is (v1+v2)/2. And since he comes back to the starting point (his house) net displacement will be 0. Hope it is clear!