Question

4.a. The sum of the digits of a two-digit number is 15. If the number formed by reversing
the digits is less than the original number by 27, find
the original number.​

Answer 1

Answer:

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ANSWER

ANSWERLet the unit's place=x

ANSWERLet the unit's place=xThen the ten's place=15−x

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9x

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we get

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27⇒−18x=27−165=−108

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27⇒−18x=27−165=−108⇒x=

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27⇒−18x=27−165=−108⇒x= −18

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27⇒−18x=27−165=−108⇒x= −18−108

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27⇒−18x=27−165=−108⇒x= −18−108

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27⇒−18x=27−165=−108⇒x= −18−108 =6

ANSWERLet the unit's place=xThen the ten's place=15−x∴ original number=10(15−x)+x=150−10x+x=150−9xBy reversing the digits, we getNew number=10x+(15−x)=10x+15−x=9x−15According to the problem,original number−New number=27⇒150−9x−9x+15=27⇒−18x+165=27⇒−18x=27−165=−108⇒x= −18−108 =6Hence original number=150−9x=150−9×6=150−54=96

hope it will help you mark as brainlist answer

Answer 2

Answer:

x+y=15

y-x=27

Step-by-step explanation:

y=27+x

x+27+x=15

x^2=15-27

x^2=-8

x=-2√2

y-2√2=27

y=27+2√2

y=29√2

I hope it's help you