4. a train travel a distance of 250km at a
uniform speed. if the speed had been 5 km
less, then it would have taken 5/2 hours
more to cover the same distance. find the
speed.
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Answer:
Let speed be x
T=360/x
If speed is increased by 5 km/h
speed will be (x+5)km/h
distance is the same
T= 360/(x+5)
time with original speed - time with increased speed = 1
360/x - 360/(x+5)=1
LCD= x(x+5)
(360(x+5)-360x) /x(x+5)=1
360x+1800-360x=x(x+5)
x^2+5x = 1800
x^2+5x-1800=0
x^2+45x-40x-1800=0
x(x+45)-40(x+45)=0
(x-40)(x+45)=0
x= 40 mph the original speed ,i;e speed of train is 40 mph
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