Question

4) A wire, is in the shape of a square of
side 10cm . If wire is rebent into a rectangle
of length 12 cm find it's libreadth 1 which
encloses
more area, the square or the
Rectangle?​

Answer 1

Answer :

perimeter of square = P of rect.

4×10. = 4×10

40 =. 40

length of rect . = 12

Breadth of rect = P/2- length

= 40/2-12

= 18 cm

area of sq. = 10×10

= 100 cm sq.

area of rect. = 12×18

= 216 cm sq.

hence , area of rectangle is greater.

Answer 2

Answer:

Please mark me as brainliest..

Step-by-step explanation:

Side of the square = 10 cm

Length of the wire = Perimeter of the square

= 4 x side

= 4 x 10cm

= 40 cm

Length of the rectangle, l = 12 cm. Let b be the breadth of the rectangle.

Perimeter of rectangle Length of wire = 40 cm

Perimeter of the rectangle = 2 (l + b)

40 = 2 (12 + b)

(OR) 40 / 2 = 12 + b

b = 20 - 12 = 8 cm

Therefore,The breadth of the rectangle is 8 cm.

Area of the square = (side)²

= 10 cm × 10 cm = 100cm²

Area of the rectangle = l × b

= 12cm × 8cm = 96cm²

So , the square encloses more area even though its perimeter is the same as that of the rectangle.