4(a²+b²+2ab)-[4(a²+b²-2ab)-{-b³+4(a-3)}]
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Answered by
6
Answer:
4a²+4b²+8ab-(4a²+4b²-8ab+b³-4a+12)
4a²-4a²+4b²-4b²+8ab+8ab-b³+4a-12
16ab-b³+4a-12
Answered by
0
Answer:
a= 3 b= 1
4(a² + b² + 2ab) - [ 4(a² + b² - 2ab) - {-b³ + 4(a-3)} ]
4(a² + b² + 2ab) - [ 4(a² + b² - 2ab) - {-b³ + 4a-12} ]
4a² + 4b² + 8ab - [ 4a² +4b² - 8ab) - {-b³ + 4a-12} ]
4a² + 4b² + 8ab - [ 4a² +4b² - 8ab+ b³ - 4a+ 12} ]
4a² + 4b² + 8ab - 4a² - 4b² + 8ab - b³ + 4a-12}
4a² - 4a² + 4b² - 4b² + 8ab + 8ab - b³ + 4a-12
16ab - b³ + 4a-12
16x3x1 - (1³) + 4x3 - 12
48 - 1 + 12 - 12
47+0
47
Step-by-step explanation:
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