4(ab-cd)² - (a²+b²-c²-d²) ²
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ANSWER:-
(a²-b²-c²+d²)²-4(ad-bc)²
= (a²-b²-c²+d²)²-(2ad-2bc)²
= (a²-b²-c²+d²+2ad-2bc) (a²-b²-c²+d²-2ad+2bc)
= {(a+d)²-(b+c)²} {(a-d)²-(b-c)²}
= (a+d+b+c) (a+d-b-c) (a-d+b-c) (a-d-b+c)
= (a+b+c+d) (a-b-c+d) (a+b-c-d) (a-b+c-d)
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