Question

4. ABCD is a parallelogram in which angleDAB = 70° and ZCBD= 55º. Find angleCDB and
angleADB.​

Answer 1

Answer:

Step-by-step explan∠ADB=55°

∠CDB=55°

Step-by-step explanation:

IN //gm ABCD

∠DAB =∠BCD

∴∠BCD =70°

now,

IN ΔBCD,

∠CBD+∠BCD+∠CDB=180°          (ASP)

55°+70°+∠CDB=180°

∴∠CDB=55°

∠CBD=∠ADB            (ALTERNATE INTERIOR ∠LE)

∴∠ADB=55°

ation: