Question

4. ABCD is a rhombus whose diagonals intersect at O. Show that triangle AOB = triangle COD.​

Answer 1

Answer:

triangle AOB congruent to triangle COD since AB = CD and AO=CO and OB=OD by SSS congruency the are similar therefore area of congruent triangles are equal

Answer 2

we know that diagonals of rhombus bisect each other

so OA=OC

and OB = OD

In triangle AOB and COD

OA=OB[proved above]

OB=OD [proved above]

angle AOB = angle COD [ vertically opposite angle]

therefore triangle AOB = triangle COD [ by SAS]