4. ABCD is a trapezium with AB parallel to
DC. If AB = 10 cm, AD = BC = 4 cm and
DAB = CBA = 60°, calculate
(i) the length of CD,
(ii) the distance between AB and CD
Answers
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2
Answer:
the length of CD=10,becauseAB=CD
and distance between AB and CD=4 ,because length of BC and AD is 4
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