Question

4. ABCD is a trapezium with AB parallel to
DC. If AB = 10 cm, AD = BC = 4 cm and
DAB = CBA = 60°, calculate
(i) the length of CD,
(ii) the distance between AB and CD​

Answer 1

Answer:

the length of CD=10,becauseAB=CD

and distance between AB and CD=4 ,because length of BC and AD is 4