Question

А.
4 AD is an altitude of an isosceles AABC in
which AB = AC.
Show that (i) AD bisects BC,
(ii) AD bisects LA.
B
D
C​

Answer 1

Answer:

AD bisects BC

AB=AC ,angle ADB =90 ADC=90 , AD=AD common,

so AD bisects BC

so BD= CD