Question

4 adding 3 times a number is 201. Find the number​

Answer 1

Let the unknown no: be => ' x '

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201 => 3x = 197

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201 => 3x = 197 => x = 197 ÷ 3

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201 => 3x = 197 => x = 197 ÷ 3 => x = 65.6

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201 => 3x = 197 => x = 197 ÷ 3 => x = 65.6 Your required ANS is above

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201 => 3x = 197 => x = 197 ÷ 3 => x = 65.6 Your required ANS is abovePlease do check it

Let the unknown no: be => ' x ' According to the question : 4 + 3 ( x ) = 201 => 3x = 197 => x = 197 ÷ 3 => x = 65.6 Your required ANS is abovePlease do check itPlease mark my ans as a BRAINLIEST

Answer 2

Answer:

x=63

Step-by-step explanation:

3x+4=201

x+4=201÷3

x+4=67

x=67-4

∴x=63