Question

4. *
Age of a daughter is 3 more than that of son. Age of father is three times that of son. If the sum of the age of father
and the daughter is 67. Find their age?
Your answer​

Answer 1

Answer: age of son is 16 yrs

age of daughter= 19yrs

age of father= 48 yrs

Step-by-step explanation:

Let age of son be x years,

therefore, age of daughter= (3+x)

age of father= (3x)

According to question,

(3x) + (3+x) = 67

3x + 3 + x = 67

4x = 67-3

x= 64/4

x = 16

Hence, age of son is 16 yrs, age of daughter (x+3)= 19yrs and age of father(3x)= 48 yrs

Thank u!

Answer 2

Answer :

$\star\boxed{\bf{Daughter\:=\:19\:Years}}\star\\\star\boxed{\bf{Son\:=\:16\:Years}}\star\\\star\boxed{\bf{Father\:=\:48\:Years}}\:\star$

Explanation :

Given :–

• Age of Daughter is 3 more than Son .
• Age of Father is three times of the Son .
• Sum of the age of Father  and the Daughter is 67 .

To Find :–

The ages of Father , Daughter and Son .

Solution :–

Let the age of Daughter , Son and Father be x , y and z Respectively .

According to the First Condition :-

⇒ x = y + 3  -------------(1)

According to the Second Condition :-

⇒ z = 3y  -----------(2)

According to the Third Condition :-

⇒ x + z = 67  ------------(3)

Putting z from Equation(2) in Equation(3) :-

⇒ x + 3y = 67

⇒ x = 67 - 3y  ------------(4)

Substituting the value of x from Equation(1) and Equation(4) :-

⇒ 67 - 3y = y + 3

⇒ 3y + y = 67 - 3

⇒ 4y = 64

⇒ y = 64/4

⇒ y = 16 years

Putting the value of 'y' in Equation(4) :-

⇒ x = 67 - 3(16)

⇒ x = 67 - 48

⇒ x = 19 years

Putting the value of 'y' in Equation(2) :-

⇒ z = 3(16)

⇒ z = 48 years

∴ The age of Daughter , Son and Father are 19 , 16 and 48 Years Respectively .