Math, asked by dipaksvrp, 4 months ago

4. Ajeeta starts off from home at 7 a.m. with her father on a scooter that goes at a uniform
speed of 30 km/hr. Her father drops her at her school after half an hour. She stays in the
school till 1.30 p.m. and takes an autorickshaw to return home. The autorickshaw has a
uniform speed of 10 km/hr. Draw the line graph for the given situation and also determine
the distance of Ajeeta's school from her home.​

Answers

Answered by Anonymous
1

 \underline{ \underline{  \tt{ Question -}}}

4. Ajeeta starts off from home at 7 a.m. with her father on a scooter that goes at a uniform speed of 30 km/hr. Her father drops her at her school after half an hour. She stays in the school till 1.30 p.m. and takes an autorickshaw to return home. The autorickshaw has a uniform speed of 10 km/hr. Draw the line graph for the given situation and also determine

the distance of Ajeeta's school from her home.

 \underline{ \underline{ \tt{Given -}}}

Time when ajita starts off from home - 7 a.m.

Speed = 30 km/hr

Her father drops after = 30 hrs.

She stays in school = 1.30 p.m.

Speed of autorickshaw = 10 km/hr.

 \underline{ \underline{ \tt{To  \: find -}}}

Distance of Ajeeta's school from her home.

 \underline{ \underline{ \tt{Solution -}}}

We know that,

 \boxed{ \blue{ \underline{ \tt{speed =  \frac{distance}{time} }}}}

 \tt{ : \implies \: 30  =  \dfrac{distance}{ \frac{1}{2} } } \\  \\  \tt{ \ \: :  \implies \:30 =  \frac{distance}{2}  } \\  \\  \tt{ :  \implies \: distance =  \frac{ \cancel{30}  \: ^{15} }{ \cancel2} } \\  \\   \boxed{ \blue{ \underline{\bold{ \therefore \: distance = 15 \: km}}}}

____________________________

________

@Miss_Solitary ✌️

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Answered by UniqueBabe
2

Answer:

We know that,

\boxed{ \blue{ \underline{ \tt{speed = \frac{distance}{time} }}}}

speed=

time

distance

\begin{gathered} \tt{ : \implies \: 30 = \dfrac{distance}{ \frac{1}{2} } } \\ \\ \tt{ \ \: : \implies \:30 = \frac{distance}{2} } \\ \\ \tt{ : \implies \: distance = \frac{ \cancel{30} \: ^{15} }{ \cancel2} } \\ \\ \boxed{ \blue{ \underline{\bold{ \therefore \: distance = 15 \: km}}}}\end{gathered}

:⟹30=

2

1

distance

:⟹30=

2

distance

:⟹distance=

2

30

15

∴distance=15km

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