4 Al + 3 O2 –> 2 Al2O3
How much aluminum would be needed to completely react with 45 grams of O2?
PLS EXPLAIN!!!
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Answer:
No. of moles of Aluminium =
27
1.08
=0.04 moles
No. of moles of Oxygen =
32
0.99
=0.031 moles
For 4 moles of Al we need 3 moles of O
2
0.04 moles of Al we need 0.03 moles of O
2
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Explanation:
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