4. An archer pulls back the arrow in his bow a distance of 0.5 m against an average force of 300 N. a) How much work is done? b) What are the energy changes here?
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1000 Newton is the right answer
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150Nm
Work = Force × displacement
= 300N × 0.5m
= 150Nm
Muscular energy is changed to mechanical energy which is potential energy here. When the bow is released, the potential energy is transformed into kinetic energy.
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