Physics, asked by scalav, 6 months ago

4. An archer pulls back the arrow in his bow a distance of 0.5 m against an average force of 300 N. a) How much work is done? b) What are the energy changes here?

Answers

Answered by boss001gamer
0

Answer:

1000 Newton is the right answer

mark me brainly answers

Answered by anis92
1

150Nm

Work = Force × displacement

= 300N × 0.5m

= 150Nm

Muscular energy is changed to mechanical energy which is potential energy here. When the bow is released, the potential energy is transformed into kinetic energy.

Similar questions