4)An automobile travels from city A to city B and returns to city A by the same route. The
speed of the vehicle during the onward and return journeys were constant at 60 km/h and
90 km/h, respectively. What is the average speed in km/h for the entire journey?
Answers
Answered by
16
Given:
distance covered is same...
&
Speeds were = 60 km/ht nd 90km/hr
therefore,
Average speed = (60 + 90)/2 km/hr = (150/2) km/hr = 75 km/hr...
Average speed = 75 km/hr...
hope it helps...
distance covered is same...
&
Speeds were = 60 km/ht nd 90km/hr
therefore,
Average speed = (60 + 90)/2 km/hr = (150/2) km/hr = 75 km/hr...
Average speed = 75 km/hr...
hope it helps...
Answered by
1
since equal distances are covered at 60 kmph and 40 kmph, we can apply the formula 2xy/(x+y)
Average speed=
2
×
40
×
60
40
+
60
= 48 kmph
This formula works as follows
Let the distance to one side = x
Total distance = 2x
Time taken for the forward journey =
x
60
Time taken for the return journey =
x
40
Total time =
x
60
+
x
40
=
100
x
2400
Average speed =
Total distance
Total Time
=
2
x
(
100
x
2400
)
= 48 kmph
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