Question

4 An electric heater of resistance 500 22 is connected to a mains supply
for 30 min. If 15A current flows through the filament of the heater, then
calculate the heat energy produced in the heater.​

Answer 1

hope it works for you ..

Answer 2

Answer:- 20.25 × 10^7 J

Solution:-

Given, I = 15A

R = 500 Ohm

T = 30min = (30×60)sec

Put these values in H = I²RT

• H = (15)² × 500 × 30 × 60
• H = 202500000
• H = 20.25 × 10^7 J

☺✌