4.An electric train is moving with a velocity 120 km/h. How much distance will it
move in 40 s?
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Answer:
The Train will cover 2400 m or, 2.4 km.
Explanation:
Final Velocity (v) = 120 km/hr
Initial Velocity (u) = 0 km/hr
Time (t) = 40 s
Acceleration (a) = [v-u]/t
= [120/40] m/s²
= 3 m/s²
According to formula,
= v² = u²+2aS .... Here, 'S' is the distance
= (120)² = 0² + 2[3S]
= 14400 = 6S
= S = 2400 m
Hope this helps.
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