Physics, asked by sdalhna6, 16 days ago

4. An inductor of 10 mH is connected to an ac source of voltage 200 V and 50Hz. Calculate the inductive reactance and the current in the circuit.

Answers

Answered by sandeepsingh54577
0

Answer:

The reactance of the inductor is

XL=ωL=(2π×50s-1)×(200×10-3H)

=62.8Ω

The peak current is

i0=

ε0

XL

=

210V

72.8Ω

=33.A.

As the current lags behind the voltage by

π

2

, the voltuage is zero when the current has it peak value.

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