4 anglesof a quadrilateral are in the ratio 5:2:3:8 . Find the angles.
A solid has 40 faces , 60 edges. Find the no. Of vertices
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1.
let the angles be 5 x , 2 x ,3 x and 8 x
we know that in a quadrilateral the sum of all the interior angles is equal to 360°
so according to question
5 x + 2 X + 3 X + 8 x is equal to 360
18x=360
x=360/18=20
so the angles of
5x=5×20=100 degrees
2x=2×20=40 degrees
3x=3×20=60 degrees
8x=8×20=160 degrees
2.
V + F –E=2
V=2+E-F
V=2+60-40
=62-40
=22
HERE IS UR ANSWER
HOPE IT HELPS
1.
let the angles be 5 x , 2 x ,3 x and 8 x
we know that in a quadrilateral the sum of all the interior angles is equal to 360°
so according to question
5 x + 2 X + 3 X + 8 x is equal to 360
18x=360
x=360/18=20
so the angles of
5x=5×20=100 degrees
2x=2×20=40 degrees
3x=3×20=60 degrees
8x=8×20=160 degrees
2.
V + F –E=2
V=2+E-F
V=2+60-40
=62-40
=22
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