Question

4.
answer is 29 and 15 prove it
please tell me the ans step by step plzz ......
give me the answer as soon as possible​

Answer 1

Answer:

ANSWER

Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.

To find : the two numbers

Let x and y be the two numbers required.

According to the question :

⇒2x+3y=92 ........(1)

⇒4x−7y=2 ........(2)

multiply the first equation by 2 , and subtract eqn (1) from eqn (2)

4x+6y=184

−(4x−7y=2) , we get

⇒13y=182

⇒y=

13

182

=14

Put y=14 in (1)

2x+3y=92

⇒2x+3×14=92

⇒2x=92−42=50

∴x=

2

50

=25

∴x=25 and y=14

BUT YOU HAVE TO FOLLOW ME

Answer 2

Answer:

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