4. Balls numbered from 8 to 128 are put in a bag. Now one ball is drawn at random from the bag, find the probability that it is a
A. Perfect square number
B. Perfect cube number
C. Either a multiple of 11 or a factor of 64.
D. Neither an even prime number nor an odd composite number
Answers
ANSWER
Solution(i):
Let E be the event of drawing an odd-numbered card from the cards numbered 1 to 49
Odd numbers from 1 to 49=1,3,5,.....,49
No. of favorable outcomes=25
Total no. of possible outcomes =49
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
49
25
Therefore, the probability of an odd number card from the cards numbered 1 to 49=
49
25
Solution(ii):
Let G be the event of drawing a number - multiple of 5 from the cards numbered from 1 to 49
Multiples of 5 from 1 to 49=5,10,15,20,25,30,35,40,45
No. of favorable outcomes=9
Total no. of possible outcomes =49
We know that, Probability P(G) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
49
9
Therefore, the probability of drawing a multiple of 5 from the cards numbered from 1 to 49=
49
9
Solution(iii):
Let F be the event of drawing a perfect square number from the cards numbered from 1 to 49
Perfect square numbers from 1 to 49=1,4,9,16,25,36,49
No. of favorable outcomes=7
Total no. of possible outcomes =49
We know that, Probability P(F) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
49
7
=
7
1
Therefore, the probability of drawing a perfect square number from the cards numbered from 1 to 49=
7
1
Solution(iv):
Let H be the event of drawing an even prime number from the cards numbered 1 to 49
Even prime number from 1 to 49=2 (2 is the only even prime number )
No. of favorable outcomes=1
Total no. of possible outcomes =49
We know that, Probability P(H) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
49
1
Therefore, the probability of drawing an even prime number from the cards numbered 1 to 49=
49
1
hope it helps please mark as brainlliest
Answer:
solution A is the correct answer