Question

4 Batteries whose Electromagnetic forces are 3 volts and internal resistance is 0.2 Ω are connected in series with a external resistance of 9.2 Ω. Find the voltage of terminals of external resistance.​

Answer 1

Explanation:

Here's your answer in the attachment

Hope it helps you

Answer 2

Explanation:

Enet = 12

rnet = 0.8

I= 12/9.2+0.8

V= 9.2*1.2 = 11.04V

Vab = IR

=12/9.2+0.8*9.2

=12/10*9.2

=1.2*9.2

=11.04 V