Question

4. BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence
rule, prove that the triangle ABC is isosceles.
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Answer 1

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Answer 2

Answer:

since in triangle BCF and triangle BCE

BC=BC(common)

CF=BE (given)

angle BFC= angle CEB (90 °)

so triangle BCF=triangle BCE (by RHS rule)

angle B=angle C( by CPCT rule)

then AC=AB ( side opposite to equal angel are equal