4 bells toll together at 9.00 am. they toll after 7, 8, 11 and 12 seconds respectively. how many times will they toll together again in the next 3 hours?
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given 4 bells ring together at 9.00 am
four bells ring respectively at 7, 8, 11, 12 seconds
no of times all four bells in next 3 hours,
7 = 1*7
8 = 1*2*2*2
11 = 1*11
12 = 1*2*2*3
LCM of 7, 8, 11, 12 is (1*2*2*2*3*7*11) 1848 seconds = 1848/60min = 30min+48second
in 3hours has 3*60 = 180 min
5(30min+48sec) = 150min+240sec = 150+4 min = 154 min
so from 9.00am to 12.00pm(in 3 hours) all four clocks ring together for 5 times in 3 hours
four bells ring respectively at 7, 8, 11, 12 seconds
no of times all four bells in next 3 hours,
7 = 1*7
8 = 1*2*2*2
11 = 1*11
12 = 1*2*2*3
LCM of 7, 8, 11, 12 is (1*2*2*2*3*7*11) 1848 seconds = 1848/60min = 30min+48second
in 3hours has 3*60 = 180 min
5(30min+48sec) = 150min+240sec = 150+4 min = 154 min
so from 9.00am to 12.00pm(in 3 hours) all four clocks ring together for 5 times in 3 hours
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