Question

4 boys and 2 girls occupy seats in a row at random. Then, the probability that the two girls occupy seats side by side is

Answer 1

Answer:

Step-by-step explanation:

total number of ways  =  6P6 = 6!

NUMBER OF WAYS

     GIRLS TO  OCCUPY SIDE SEATS = 2P2

now the number of ways boys arranged = 4P4

SO NUBER OF WAYS IN FAVOUR        = 2P2x4P4 =2!x4!

the probability that the two girls

              occupy seats side by side is = 2!x4!/6! = 2/[5x6] =2/30=1/15