Math, asked by rohitkotwal20, 9 months ago

4 boys from school A and 6 boys from school B together can set up exhibition in 5 days, which 5 boys from school A and 10 boys from school C together can do in 4 days or 3 boys from school B and 4 boys from school C together can do in 10 days. Then how many boys from school A can set up the exhibition in one day?​

Answers

Answered by amitnrw
0

40 Boys from School A can setup Exhibition in 1 Day

Step-by-step explanation:

4 boys from school A and 6 boys from school B together can set up exhibition in 5 days

(4A  + 6B)5  =  Work

=> 20A + 30B  = Work

5 boys from school A and 10 boys from school C together can do in 4 days

(5A + 10C)4  =  Work

=> 20A + 40C  = Work

=> 30B = 40C  => 3B = 4C

3 boys from school B and 4 boys from school C together can do in 10 days

(3B  + 4C)10  = Work

=> 30B  + 40C = Work

=> 60B = Work

20A + 30B = 60B

=> 20A = 30B

=> 40A = 60B

   60B = Work

=> 40A = Work

40 Boys from School A can setup Exhibition in 1 Day

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