Chemistry, asked by uditpadhan98, 11 months ago

4-bromo-1-butanol (A) can be converted into 5-hydroxy pentanoic acid (B) by following
method(s)
I. A Mg/ether (1)CO, B
(ii) H20+
II. A- KCN +
H2O
+B
III. A
aq. KOH
KMnO, /H*
B
Select the correct alternate.
(a) I, II and III
(b) I and II
(c) II and III
(d) Only II​

Answers

Answered by rahul808764
2

Answer:

i think....

ii and ii option c correct.

Answered by Brainzeee
0

Answer:

The correct answer is Option (d) Only ll.

Explanation:

1. In case-l:

  • 4-bromo-1-butabol (A) when it reacts with Mg/ ether, then CO2 and H3O+ , it forms MgBr-CH2-CH2-CH2-CH2-OH.
  • In which -MgBr and -OH are decomposed by alcohol group.
  • So, 5-hydroxy pentanoic acid (B) does not form.
  • So, case-l is not possible.

2. In case- ll:

  • 4-bromo-1-butanol (A) when it reacts with KCN and H3O+, it forms 5-hydroxy pentanoic acid (B).
  • So, case-ll is possible.

3. In case-lll:

  • When 4-bromo-1-butanol (A) when reacts with KOH and then KMnO4 / H+, CN-CH2-CH2-CH2-CH2-OH form.
  • In which -CN and -OH both are oxidized to -COOH and does not form 5-hydroxy pentanoic acid (B).
  • So, case-lll is not possible.

Find attached photo for better understanding.

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