4-bromo-1-butanol (A) can be converted into 5-hydroxy pentanoic acid (B) by following
method(s)
I. A Mg/ether (1)CO, B
(ii) H20+
II. A- KCN +
H2O
+B
III. A
aq. KOH
KMnO, /H*
B
Select the correct alternate.
(a) I, II and III
(b) I and II
(c) II and III
(d) Only II
Answers
Answered by
2
Answer:
i think....
ii and ii option c correct.
Answered by
0
Answer:
The correct answer is Option (d) Only ll.
Explanation:
1. In case-l:
- 4-bromo-1-butabol (A) when it reacts with Mg/ ether, then CO2 and H3O+ , it forms MgBr-CH2-CH2-CH2-CH2-OH.
- In which -MgBr and -OH are decomposed by alcohol group.
- So, 5-hydroxy pentanoic acid (B) does not form.
- So, case-l is not possible.
2. In case- ll:
- 4-bromo-1-butanol (A) when it reacts with KCN and H3O+, it forms 5-hydroxy pentanoic acid (B).
- So, case-ll is possible.
3. In case-lll:
- When 4-bromo-1-butanol (A) when reacts with KOH and then KMnO4 / H+, CN-CH2-CH2-CH2-CH2-OH form.
- In which -CN and -OH both are oxidized to -COOH and does not form 5-hydroxy pentanoic acid (B).
- So, case-lll is not possible.
Find attached photo for better understanding.
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