4
(c) In the figure (3) given below, AD is perpendicular to BC, BD = 15 cm,
sin B = and tan C = 1.
(i) Calculate the lengths of AD, AB, DC and AC.
5
Answers
Answered by
2
ANSWER
In △ABC, AD⊥BC, sinB=0.8, tanC=1, BD=9
In △ABD,
sinB=0.8
cos
2
B=1−sin
2
B=1−(0.8)
2
cosB=(0.6)
2
cosB=0.6
cosB=
AB
BD
AB=
0.6
BD
AB=
0.6
9
=15
Also, using Pythagoras theorem,
AB
2
=AD
2
+BD
2
15
2
=9
2
+AD
2
AD=144
AD=12 cm
Now, In △ACD
tanC=1=
B
P
=
CD
AD
AD=CD=12 cm
Using Pythagoras theorem,
AD
2
+CD
2
=AC
2
12
2
+12
2
=AC
2
AC=12
2
cm
Answered by
12
Here u go with ur answer.....hope it helps...
And really sry fr the bad handwriting
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