Question

4. C is the centre of the circle whose radius is 10 cm. Find the distance of the
chord from the centre if the length of the chord is 12 cm.​

Answer 1

The answer is 8 cm(the distance between the chord and centre)

Answer 2

HEY MATE YOUR ANSWER IS HERE...

ACCORDING TO THE QUESTION...

★ GIVEN ★

• c is the center of circle

• AB be the chord ( 12cm )

• AC be the radius (10 cm )

★ TO FIND ★

• length of DC (distance of thechord from the centre)

★ FIGURE ★

• REFER TO THE ATTACHMENT

★ PROOF ★

AD = DB ------- eq 1

AD + DB = AB

AD + DB = 12 cm ( as AB = 12cm )

AD + AD = 12 cm ( from eq 1 )

2AD = 12cm

AD = 6 cm

NOW IN TRIANGLE ACD

angle CDA = 90°

THUS ,

TRIANGLE ADC IS RIGHT ANGLE TRIANGLE....

NOW BY PYTHAGORAS THEOREAM..

AC² = AD² + DC²

10² = 6² + DC² ( GIVEN AC = 10 cm )

100 = 36 + DC²

100 - 36 = DC²

64 = DC²

8 = DC

HENCE

★ LENGTH OF DC = 8 cm ★

THANKS FOR UR QUESTION

HOPE IT HELPS

KEEP SMILING ☺️☺️☺️☺️✌️