4. Calculate the amount of 'Al' required to get 2240 kg of Iron
from the below equation:[Al =27U, Fe= 560, 0=160] al+fe2o3=al2o3 +fe
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Answered by
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Explanation:
Let's consider the equation first.
F
e
2
O
3
+
2
A
l
=
A
l
2
O
3
+
2
F
e
It says that 2 moles of aluminium will react with 1 mole of Iron (III) Oxide to form 1 mole of Aluminium Oxide and 2 moles of Iron.
So, Unitary method.
54
g Al will react with
→
160
g of
F
e
2
O
3
1
g Al will react with
→
160
54
g of
F
e
2
O
3
52.6
g Al will react with
→
160
⋅
52.6
54
g of
F
e
2
O
3
≈
155.85
g of
F
e
2
O
3
Hence Explained.
I think this will help you
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