Question

4. Calculate the mass of copper nitrate obtained by treating 6.4 g of copper with excess of concentrated
nitric acid. (Cu = 64, N = 14, 0 = 16)​

Answer 1

Answer:

18.8 g Cu(NO3)2

Explanation:

4HNO3 > 2H2O + 4NO2 + O2

2Cu + O2 > 2CuO

2CuO + 4HNO3 > 2Cu(NO3)2 +2H2O

Complete reaction:

2Cu+ 8HNO3 > 2Cu(NO3)2+4NO2+4H2O

2×64 g Cu = [2{64+(14+16×3)×2}] g Cu(NO3)2

6.4g Cu = [2{64+(14+16×3)×2}]×6.4 /2×64

= 18.8 g Cu(NO3)2