4.Calculate the mass percent of Na,P& O in Na3PO4 (Atomic mass of Na=23,P= 30.9
Answers
Answered by
1
Answer:
answer in explanation .
Explanation:
The molar mass of sodium phosphate is
M
r
=
(
3
×
23
)
+
31
+
(
4
×
16
)
=
164
g
/
m
o
l
.
Now consider 1 mole of
N
a
3
P
O
4
which has a mass of
164
g
:
3
×
23
=
69
g
is sodium,
31
g
is phosphorous,
4
×
16
=
64
g
is oxygen.
Therefore the percentage composition of each element is:
69
164
×
100
=
42.1
%
N
a
31
164
×
100
=
18.9
%
P
64
164
×
100
=
39
%
O
Answered by
2
Answer:
Mass percent of Na = 42.1 , P = 18.9 and
O = 39.04.
Step by step explanation:
The molar mass of sodium phosphate is
Mr =(3×23)+31+(4×16) = 164 g/mol
Now consider 1 mole of Na3PO4 which has a mass of 164g
3×23 = 69 g is sodium,31 g is phosphorus,4×16 = 64g is oxygen
68÷164×100 = 42.1 % Na
31÷164×100 = 18.9 % P
64÷164×100 = 39 % O
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