Question

4. Calculate the molality of solution containing 3 g glucose dissolved in 30 g of water. (molar mass of glucose
= 180)
(1) 0.50 m
(2) 0.56 m
(3) 0.091 m
(4) 0.05 m
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Answer 1

Answer:

(2) 0.56 m

Explanation:

Moles of glucose =3/180=1/60 moles

Molality= Moles of solute/Mass of solvent(Kg) =

1×1000/60×30=5/9 =0.56 m

Hence option (2) is correct answer

Answer 2

Answer:

Answer is

2) 0.56m

Explanation:

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