Question

4. Calculate the net(equivalent) resistance of the circuit if resistances of 10 Ω, 5 Ω and 15 Ω are connected in parallel.

Answer 1

Answer:

$\huge\purple {\mathfrak{Bonjour Mate!}}$

resistors of resistances R1 and R2 are connected in series, as shown: Equivalent resistance of the circuit is given as: R = R1 + R2 = 5 + 10 = 15 Ω According to Ohm’s law: V = IR Where, V = emf of the battery = 6 V I = Total current flowing through the circuit (ii) For maximum current flowing Two resistors of resistances R1 and R2 are connected in parallel, as shown: Equivalent resistance of the circuit is given as: According to Ohm’s law: V = IR Where, V = emf of the battery = 6 V I = Total current flowing through the circuit

Answer 2

Answer:

1/R = 11/30

which is approximately 2.7 ohms