Question

4. Calculate the number of formula units in 3.25 mol of silver nitrate.

Answer 1

Answer:

AgNO 3 = 3.25 mol AgNO × 6.02 × 10 23 f.

Explanation:

Answer 2

Answer:

The number of formula units in $3.25mol$ of silver nitrate ( $AgNO_{3}$ ) calculated are $1.95\times 10^{24}$ units/mol.

Explanation:

Data given,

The number of moles of silver nitrate ( $AgNO_{3}$ ), n = $3.25mol$

The number of formula units in $3.25mol$ of silver nitrate ( $AgNO_{3}$ ) =?

As we know,

• The number of formula units in 1 mole = $6.022\times 10^{23}$ units/mole

Therefore,

• The formula unit's number in $3.25$ mole = $3.25\times 6.022\times 10^{23}$ units/mol
• The formula unit's number in $3.25$ mole = $1.95\times 10^{24}$ units/mol

Hence, the number of formula units in $3.25mol$ of silver nitrate ( $AgNO_{3}$ ) calculated are $1.95\times 10^{24}$ units/mol.