Question

4)Calculate the pH of 0.003 M KOH solution.
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Answer 1

Ph=11.5

is the answer of this question

Answer 2

Answer:

p H ≈ 11.5

Explanation:

When put in water, the  K O H  dissolves into  K +  and  O H −  ions, with the latter increasing the  p H  of the solution.

As hydroxides can be considered strong bases, it will completely dissociate into the water solution, and form an equal amount of moles of hydroxide ions:

0.003 mol of  O H −.

Now,

p O H = − log [ O H − ]  p O H = 2.522

And if we assume this is done under standard conditions:

p O H + p H = 14

p H = 14 − 2.522

p H≈ 11.5