4. Calculate the % relative abundance of B -10 and B -11, if its average atomic mass is 10.804 amu.
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Answer:
Let B-10 = x%
and B-11 = (100-x)%
average atomic mass = 10x + (100 - x)/100 = 10.80
10x + 11(100 - x) = 1080
10x + 1100 - 11x = 1080
x = 20
B-10 = 20% and B-11 = (100-20) = 80%
Thus, the percentage of a heavier isotope is 80%.
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